4x^2-32x+48/3x^2-17x-6

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Solution for 4x^2-32x+48/3x^2-17x-6 equation: 


x in (-oo:+oo)

4*x^2+(48/3)*x^2-(32*x)-(17*x)-6 = 0

4*x^2+(48/3)*x^2-32*x-17*x-6 = 0

20*x^2-49*x-6 = 0

DELTA = (-49)^2-(-6*4*20)

DELTA = 2881

DELTA > 0

x = (2881^(1/2)+49)/(2*20) or x = (49-2881^(1/2))/(2*20)

x = (2881^(1/2)+49)/40 or x = (49-2881^(1/2))/40

x in { (49-2881^(1/2))/40, (2881^(1/2)+49)/40 }

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